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Consider N2O4 (g) ---> 2 NO2 (g) . 3.00 X 10-2 mol of N2O4 are placed in...

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Chemistry

Consider N2O4 (g) ---> 2 NO2(g) . 3.00 X 10-2 mol of N2O4 areplaced in a 1.0 L flask. AT equilibrium, 2.36 X 10-2 molof N2O4 remain. What is the Keq for thisreaction?

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3.7 Ratings (320 Votes)

                                 N2O4 (g)              --->              2 NO2 (g)

Initial                          0.03 molar                                  0

Change                  -x                                                 x

At equilibrium              0.03-x                                     x

Keq = [NO2]^2 / [N2O4]

Given :

[N2O4] = x = 0.0236 molar

so [NO2] = 0.03- 0.0236 = 0.0064 molar

so Keq = 0.0064 / (0.0236)^2 = 11.49
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