Consider a 0.487 L solution of the amino aspartic acid (0.685 M), which ahs a carboxylic...

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Consider a 0.487 L solution of the amino aspartic acid (0.685M), which ahs a carboxylic acid group (pKa = 2.10), an amine group(pKa = 9.82), and a carboxylic acid side chain (pKa = 3.86). Howmany liters of 2.59 M NaOH would you need to add to reach theisoelectric point of the amino acid?

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3.9 Ratings (537 Votes)

ANS)Â Â Â Â Â Â Â Â Â Â given side chainÂ Â Pka =3.86 ,acidic group Pka = 2.10

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â isoelectric point ( PH) = 3.86 + 2.10 / 2Â Â =Â Â 2.98

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â NaOHÂ Â Â Â + ASPARTIC ACIDÂ Â Â ------------Â Â Â Â Â SALTÂ Â + H2O

Â Â Â Â Â mole addedÂ Â Â Â Â Â Â Â 2.59* VÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0.487 * 0.685=0.3335Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0Â Â Â Â Â Â Â Â Â Â Â Â 0

Â Â Â Â moles after rxnÂ Â Â Â Â Â Â Â Â 0Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0.3335 -Â Â 2.59VÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 2.59VÂ Â Â Â Â Â Â Â Â Â 2.59V

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â [ ACID ] = 0.3335 -2.59V / 0.487+ VÂ Â , [ SALT ] =Â Â 2.59V / 0.487+ V

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â USING Hendersons eqÂ Â Â Â P^H = P^KaÂ Â Â^{+ log [ salt ]} / [acid ]

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 2.98Â Â =Â Â 2.10 + log [ 2.59V / 0.487+ V]Â Â /Â Â

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