Composition of Solution for Determing k Test Tube 0.0025 M Fe(NO3)3 0.0025 M KSCN 0.10 M HNO3 Results of Spectro Absorbance 6 1.0...

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Chemistry

Composition of Solution for Determing k
Test Tube 0.0025 M Fe(NO3)3 0.0025 M KSCN 0.10 M HNO3 Results of Spectro Absorbance
6 1.0 ml 1.0 ml 5.0 ml ---> .109
7 1.0 ml 1.5 ml 4.5 ml .183
8 1.0 ml 2.0 ml 4.0 ml .278
9 1.0 ml 2.5 ml 3.5 ml .295
10 1.0 ml 3.0 ml 3.0 ml .337
Test Tube Starting Fe3+ Starting SCN- Equlibrium Fe(SCN)2+ Eq. Fe3+ Eq. SCN-
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Complete the above chart with all concentrations in M. * Coulmns1 and 2 dilution occured for both Fe(NO3)3 \"Fe3+\" and KSCN \"SCN-\",Column 3 determine FeSCN2+ using A=kc, Columns 4 and 5 create andICE chart for each test tube, Column 6 determine the value of K foreach test tube of Equilibrium for Fe(SCN)2+, Fe3+, SCN-

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4.1 Ratings (595 Votes)

In order to do this I need the value of E or k as you put here With that value I can calculate concentration of FeSCN2 and then the other values In another problem I solved earlier I See Answer

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Test Tube	0.0025 M Fe(NO3)3	0.0025 M KSCN	0.10 M HNO3	Results of Spectro	Absorbance
6	1.0 ml	1.0 ml	5.0 ml	--->	.109
7	1.0 ml	1.5 ml	4.5 ml		.183
8	1.0 ml	2.0 ml	4.0 ml		.278
9	1.0 ml	2.5 ml	3.5 ml		.295
10	1.0 ml	3.0 ml	3.0 ml		.337

Test Tube	Starting Fe3+	Starting SCN-	Equlibrium Fe(SCN)2+	Eq. Fe3+	Eq. SCN-
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