first find pOH from pH
pH + pOH = 14
pOH = 14 - pHÂ Â Â = 14 - 10 = 4
from the pOH we can calculate the [HO-]
[HO-] = 10^--4 = 0.0001 M
     C18H12NO3 (aq) + H2O (l) ---->
C18H13NO3- (aq) + HO- (aq) construct ICE table
IÂ Â Â Â Â Â 0.05
MÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
0Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
0
CÂ Â Â Â Â Â
-x                                             Â
+x                     Â
+x
EÂ Â Â Â Â Â Â
0.05-x                                        Â
+x                Â
+x
from the ICE table concentration of C18H13NO3- of concetration
HO-
and we have alredy concentration of HO- = 0.001 M =
[C18H13NO3-]
conceration of C18H12NO3 = 0.05 - x = 0.05 - 0.0001 = 0.0499
M
