â€‹Co-browsing refers to the ability to have a contact center agent and customer jointly navigate an...

4.2 Ratings (843 Votes)

null hypothesis: Ho:Ï€1=Ï€2

alternative hypotheses Ha:Ï€1 â‰ Ï€2

Applying chi square test of independence:

Observed		co-browsing	Non	Total
	use	88	61	149
	not use	38	119	157
	total	126	180	306

Expected	E_i=row totalcolumn total/grand total*	co-browsing	Non	Total
	use	61.3529	87.6471	149.00
	not use	64.6471	92.3529	157.00
	total	126.00	180.00	306.00

chi squareÂ Â Â Ï‡²	=(O_i-E_i)²/E_i	co-browsing	Non	Total
	use	11.573	8.101	19.6749
	not use	10.984	7.6886	18.6723
	total	22.5572	15.7900	38.347

test statistic X² =	38.3472

degree of freedom(df) =(rows-1)*(columns-1)=	1
for 1 df and 0.01 level , critical valueÂ Â Â Â Â Â Ï‡2=	6.635

from excel: p value =chidist(38.3472,1) =0.0000

both distribution reject the null hypothesis since both have test statistic is in the critical region

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