Cl=8 F=22 (a) How many chlorine trifluoride molecules are formed in the reaction depicted above? (b) How many...

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Chemistry

Cl=8 F=22
(a) How many chlorine trifluoride molecules are formed in thereaction depicted above?
(b) How many chlorine molecules remain after the reaction hasgone to completion?
(c) How many fluoride molecules remain after the reaction hasgone to completion?
(d) Which is the limiting reactant in the reaction depictedabove?
(e) If the reaction was carried out with 2.05 moles of chlorinegas and 4.46 moles of fluorine gas, how many moles of chlorinetrifluoride would be produced?
(f) If the reaction was carried out with 2.05 g of chlorine gasand 4.46 g of fluorine gas, how many grams of chlorine trifluoridewould be produced?

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3.7 Ratings (378 Votes)

The formation of chlorine trifluoride ClF3 from chlorine molecule Cl2 and fluorine molecules F2 is Cl2 3F2 2ClF3 ie 1 mole ofCl2 react with 3 moles of F2 to from 2 moles of ClF3 Now given molecules ofCl2 8 So requited molecules ofF2 from complete reaction 83 24 But given molecules ofF2 present 22 That means we have less than required molecules ofF2 So here See Answer

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