Chloroform, CHCl3, is formed by the following reaction: CH4(g) + 3 Cl2(g) → 3 HCl(g) +...

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Chemistry

Chloroform, CHCl3, is formed by the following reaction:

CH4(g) + 3 Cl2(g) → 3 HCl(g) + CHCl3 (g)

Determine the enthalpy change for this reaction (ΔH°rxn), usingthe following:

enthalpy of formation of CHCl3 (g), ΔH°f = – 103.1 kJ/mol

                                CH4(g)+ 2 O2(g) → 2 H2O(l) +CO2(g)        ΔH°rxn = –890.4 kJ/mol

                               2 HCl (g) → H2 (g) + Cl2(g)                             ΔH°rxn= + 184.6 kJ/mol

                                C(graphite) + O2(g) →CO2(g)                    ΔH°rxn = – 393.5 kJ/mol

                                H2(g) + ½ O2(g) →H2O(l)                              ΔH°rxn= – 285.8 kJ/mol

  

+ 145.4 kJ

– 305.3 kJ

– 145.4 kJ

+ 305.3 kJ

– 103.1 kJ

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