Chemistry: Calorimetry and Heats of Reaction Mass of water in styrofoam cup: 100g Mass of KCl: 1.650g Initial...

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Chemistry

Chemistry: Calorimetry and Heats of Reaction
Mass of water in styrofoam cup: 100g
Mass of KCl: 1.650g
Initial Temperature: 20.6degC
Final Temperature: 19.6degC
q=(75g)(1.0 cal/g x degC)(-1degC)= -75cal
qreaction= -qcontents
-75 cal = 75 cal --> 0.075kCal
1.650g KCl = 0.2214 mol KCl
0.075kCal/0.02214mol = 3.39kCal mol KCl
Is this the standard heat of solution?
If this is the standard heat of solution, how would I determinethe percent error of my result?
I was given this equation:
Percent error = |lit value - exptl value/lit value| x 100
with this information:
KCl(s) --> K+(g) + Cl-(g) dH=167.1kCal/mol
K+(g) + Cl-(g --> dH=163.0 kCal/mol
KCl(s) --> K+(aq) + Cl-(aq) dH=??
I know this question was super long. I'm sorry I'm confused andI'm not really sure where to begin.

Answer & Explanation Solved by verified expert

3.7 Ratings (269 Votes)

This is simple concept based question First we will calcualte the enthalpy of solution from the given data experimental value the specific heat of water 1cal g 0C mass of water taken 100 grams See Answer

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