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Change the ones with Bold text on the code accordingly. The code within the if statement...

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Programming

Change the ones with Bold text on the code accordingly.

The code within the if statement is not doing the correctprocess. When your code goes to the c2 function it should bepassing argv[1] to it.

(side note: your program design of calling the function c1(),c2() c3() is a bit odd, but it can work)

if (argv[2] == _c2)          {            ret = c1(argv[2]);            ret = ret >> 2;//divide by 2 to make it 8 bit         }        else if (argv[2] == _c1)        {            ret = c2(argv[1]);            ret = ret >> 2;//divide by 2 to make it 8 bit // this should be done in the c2() funciton        }        else if (argv[1] == _c3)        {            ret = c3(argv[2]);            ret = ret >> 2;//divide by 2 to make it 8 bit // this should be done in the c2() funciton        }        else if (argv[1] == _c4)        {            ret = c4(argv[2]);            ret = ret >> 2;//divide by 2 to make it 8 bit  // this should be done in the c2() funciton        }        else {            cout << \"'V' - Invalid operation selection\" << endl;            exit(0);        }

Answer & Explanation Solved by verified expert
3.9 Ratings (770 Votes)
Given To change the ones with Bold text on the code accordingly if argv2 c2 ret c1argv2 ret ret 2divide by 2 to make it 8 bit else if argv2 c1 ret c2argv1 ret ret 2divide    See Answer
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