CH4(g) + Cl2(g) ï‚® CH2Cl2(g) + 2 HCl(g) Use the data in the table
below to...
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CH4(g) + Cl2(g)  CH2Cl2(g) + 2 HCl(g) Use the data in the tablebelow to calculate the standard enthalpy, ∆H˚, for the reactionabove. Substance CH4(g) CH2Cl2(g) HCl(g) ∆Hf˚, kJ•mol-1 –74.6 –95.4–92.3
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fH0CH4g 746 KJmolfH0Cl2g 0
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