: carbonyl(CO) is strong field ligand so [Ni(CO)4] should have square planar shape but by the...

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Chemistry

: carbonyl(CO) is strong field ligand so [Ni(CO)4] should havesquare planar shape but by the experiment [Ni(CO)4] istetrahedral.Explain this statement.

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CO forms a coordination bond that has both sigma and pi properties A nonbonding orbital on the CO will form the primary bond and an antibonding orbital forms a bond as well Because of this    See Answer
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