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Carbon-14 decays as follows: 14 0Â Â Â Â Â Â Â Â Â Â Â 14 Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â CÂ Â ----> eÂ Â + NÂ Â Â 6 -1Â Â Â Â Â Â Â Â Â Â Â Â Â 7 Â Â isotopic masses are 14.00307 for nitrogen-14 and 14.00324...

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Chemistry

Carbon-14 decays as follows:
_{140Â Â Â Â Â Â Â Â Â Â Â 14}
Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â CÂ Â ----> eÂ Â + NÂ Â Â
^{6-1Â Â Â Â Â Â Â Â Â Â Â Â Â 7}
Â Â isotopic masses are 14.00307 for nitrogen-14 and14.00324 for carbon-14. What energy change (kJ/moles) occurs in thebeta decay of C-14? NOTE: Do I use these two masses to get the massdefect or do I use the mass of protons and nuetrons to find themass defect of each one and then subtract the two?

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3.5 Ratings (250 Votes)

mass defect = mass of product - mass of reactant

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = (14.00307 + 0.000548579 ) - 14.00324

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 0.0003785799 amu

1 amu =1.66053892 Ã— 10^-27 kilograms

mass defect in Kg = = 0.0003785799 x 1.66053892 Ã— 10^-27 = 6.286 x 10^-31 kilograms

binding energy = mass defectÂ Â Â x C^2

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 6.286 x 10^-31 x (3 x10^8)^2

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 5.6576 x 10^-14 J

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 5.6576 x 10^-17 kJÂ Â Â Â Â Â Â Â Â Â ( divide by avagadro number = 6.023 x10^23 )

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 3.40 x 10^10 kJ /mol

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