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Carbon disulfide is prepared by heating sulfur and charcoal. The chemical equation is S2 (g) + C...

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Chemistry

Carbon disulfide is prepared by heating sulfur and charcoal. Thechemical equation is

S2 (g) + C (s) <----> CS2(g)     Kc=9.40 at 900K

How many grams of CS2(g) can be prepared by heating 12.4 molesof S2(g) with excess carbon in a 7.20 L reaction vessel held at 900K until equilibrium is attained?

Answer & Explanation Solved by verified expert
4.3 Ratings (549 Votes)

construct the ICE table

here we donot want to consider the concentration of C because it is solide and it is excess

            S2 (g)   + C (s) <----> CS2 (g)

I             12.4                            0

C            -x                                 +x

E             12.4-x                          +x

now equilibrium expression Kc

Kc = [CS2] / [S2]

9.40 = 12.4-x / x

9.4x = 12.4-x

10.4x = 12.4

x = 12.4 / 10.4

x = 1.1923 moles   = [CS2]

grams of CS2 = moles of CS2 x molar mass x CS2

= 1.1923 grams x 76.14 gram/mole

=90.7823 grams
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