Can someone please explain these problems, I don't understand, please and thank you!! The patients in the...

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Can someone please explain these problems, I don't understand,please and thank you!!

The patients in the Digoxin trial dataset can be considered apopulation of people suffering from heart failure. These patientswere examined before the drug trial began, and their heart rate andblood pressure were recorded. The mean and standard deviation ofthe variables are listed below. Each variable follows a normaldistribution.

Heart rate(beats/min)                         ? =78.8           ? = 12.66

Systolic blood pressure(mmHg)            ? = 125.8          ? =19.94

  1. A patient with a heart rate of 90 is
  1. in the middle 68% of values
  2. in the middle 95% of values (but not the middle 68%)
  3. in the 5% most extreme values
  1. The 10% of patients with the highest heart rates have z scoresgreater than 1.28 What heart rate does this value correspond to?Report your answer to 2 decimal places.
  1. Many random samples of 25 patients are selected from thispopulation, and the mean of their systolic blood pressures iscalculated. The many sample means make up a sampling distribution.What is the mean of the sampling distribution (its center)? Inother words, what is the mean of the many sample means? Report youranswer to 2 decimal places.
  1. If ? is the mean from the previous question, 68% of the samplemeans have values between
  1. ? – 0.798 and ? + 0.798
  2. ? – 3.988 and ? + 3.988
  3. ? – 7.976 and ? + 7.976
  4. ? – 19.94 and ? + 19.94
  1. The 10% of samples with the highest mean systolic bloodpressure have z scores greater than 1.282. What mean blood pressuredoes this correspond to?

Answer & Explanation Solved by verified expert
3.8 Ratings (475 Votes)
Mean heart rate 90 z Mean z 907881266 z 088 According to empirical rule 68 of data falls within the first standard deviation from the mean In this case z represents distance of 90 from mean that is 088    See Answer
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