Can I get all of the question answered in a way that I know under which...

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Can I get all of the question answered in a way that I knowunder which sub question the answer goes please.

Can I get all of the questions answered in a way that I know howit fits in the question. Some parts are explanations. Thankyou.

Q. When a pink aqueous solution of potassium permanganate,faintly acidified with dilute sulfuric acid was treated with 10%aq. hydrogen peroxide, the reaction took place with the evolutionof gas bubbles, and the pink solution was turned colorless. Furtherchemical analysis revealed that the evolved gas was oxygen, and theresulting solution contains potassium sulfate and manganese (II)sulfate; water was also formed during the same reaction. Pleaseanswer the followings:

1) Write down the balanced chemical equation for thisreaction.

2) Define the type/types of the reaction; assign the oxidationnumber of Manganese in potassium permanganate and manganese (II)sulfate. Also, offer an explanation for the color change.

3) Write down the ions present in the solution before &after the reaction. If 100 mL 0.5 M potassium permanganate wasmixed with 50 mL 2 M sulfuric acid, what will be the final pH(>7 or <7) of the solution?

4) After the completion of reaction, when evolution ofgas-bubbles ceased, what will happen if an aqueous solution ofsodium carbonate was added to the reaction mixture? Please writedown the net ionic equation.

5) If initially 5.65 g of potassium permanganate was taken forthe reaction, calculate the total mass of manganese (II) sulfatepresent in the solution after the completion of the reaction. Whatis the Manganese ion concentration of the solution (assume that thetotal volume of the final reaction mixture is 500 mL)?

Useful hints: hydrogen peroxide is a strong oxidizing agent andconsidered to be a molecular compound.

Answer & Explanation Solved by verified expert
3.6 Ratings (419 Votes)
1 Write down the reaction first KMnO4 H2O2 H2SO4 K2SO4 MnSO4 O2 H2O To balance the equation we need to assign the oxidation numbers first Mn in KMnO4 7 Mn in MnSO4 2 O in H2O2 1 O in O2 0 Change in oxidation number per atom of Mn 7 2 5 Change in oxidation number per atom of O 0 1 1 Since we have two atoms of O in H2O2 the change in oxidation number for O 12 2 To balance the reaction crossmultiply this gives 2 KMnO4 5 H2O2 H2SO4 K2SO4 2 MnSO4 5 O2 H2O Finally balance the chemical equation    See Answer
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