Calculate the weight % of acetic acid in the vinegar. Calculate your percent error. For this...

4.3 Ratings (686 Votes)

Density of vinegar = 1.01g/ml

assume volume of vinegar = 1L = 1000ml

mass of vinegar = density * volume in ml

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 1.01*1000 = 1010gm

molarity of acetic acid = 0.8488M

assume volume of acetiv acid = 1L

no of moles of acetic acid = molarity *volume in L

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 0.8488*1 = 0.8488moles

mass of acetic acidÂ Â Â Â Â Â Â = no of moles * G.M.Wt

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 0.8488*60 = 50.928gm

mass percentage of acetic acid = mass of acetic acid*100/mass of vinegar

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 50.928*100/1010

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 5.04%

percentage error = Actual mass- calculated mass*100/actual mass

But actual mass not given

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