Calculate the volume of 0.820-M NaOH solution needed to completely neutralize 112 mL of a 0.620-M solution...

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Chemistry

Calculate the volume of 0.820-M NaOH solutionneeded to completely neutralize 112 mL of a0.620-M solution of themonoprotic acid HCl.

__________ mL NaOH

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3.8 Ratings (564 Votes)

As both NaOH and HCl case, Molarity = Normality

Nbase x Vbase = Nacid X Vacid

Nbase = 0.82 M and Vbase = ?

Similarily, Nacid = 0.62 M and Vacid = 112 mL    (given)

From above relation: 0.82 X Vbase = 0.62 x 112

                                         Vbase = 0.62 x 112 / 0.82

                                         Vbase = 69.44 / 0.82

                                         Vbase = 84.68 mL


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