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calculate the volume (in milliliters) of 3.0M naoh that must be added to a 1.00M ch3cooh...

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Chemistry

calculate the volume (in milliliters) of 3.0M naoh that must beadded to a 1.00M ch3cooh solution to make a buffer having ph of4.90

Answer & Explanation Solved by verified expert
4.1 Ratings (589 Votes)

PH = 4.9

PKa = 4.74

volume of CH3COOH = 1L

no of moles of CH3COOH = molarity * volume in L

                               = 1*1 = 1 moles

no of moles of NaOH    = molarity * volume in L

                                   = 3*v

---------- CH3COOH (aq) + NaOH(aq) ---------------> CH3COONa(aq) + H2O(l)

I--------------- 1 ------------------ 3v ---------------------------------- 0

C------------- -3v --------------- -3v ----------------------------------- 3v

E ---------- 1-3v ---------------- 0 ------------------------------------ 3v

          PH = Pka + log[CH3COONa]/[CH3COOH]

         4.9 = 4.74 + log[CH3COONa]/[CH3COOH]

log[CH3COONa]/[CH3COOH] = 4.9-4.74

log[CH3COONa]/[CH3COOH] =0.16

[CH3COONa]/[CH3COOH]     = 1.4454

3v/(1-3v)   = 1.4454

3v   = 1.4454(1-3v)

v = 0.197L

volume of NaOH = 197ml   >>>>answer
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