Calculate the solubility (in gL1) of CuBr(s) (Ksp 6 3 109)in 0 57 M ...

Cu aq 2NH 3 aq CuNH 3 2 aq Kf 63 x 10 10 CuBraq Cu aq Br aq Ksp of CuBr ....

Calculate the solubility (in gÂ·Lâ€“1) of CuBr(s) (Ksp = 6.3Ã— 10â€“9) in 0.57 M NH3(aq).

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Chemistry

Calculate the solubility (in gÂ·Lâ€“1) of CuBr(s) (Ksp = 6.3Ã— 10â€“9)in 0.57 M NH3(aq).

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3.8 Ratings (473 Votes)

Cu⁺(aq) + 2NH₃(aq) <-------> Cu(NH₃)₂(aq)

Kf = 6.3 x 10¹⁰

CuBr(aq)Â Â Â Â <------->Â Â Â Â Cu⁺(aq) + Br^-(aq)

Ksp of CuBr = 6.3 x 10^-9

Adding both equations,

CuBr + 2NH₃Â Â <-------> Cu(NH₃)₂ + Br^-

K = (6.3 x 10¹⁰) x (6.3 x 10^-9) = 396.9

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â CuBrÂ Â +Â Â 2NH₃ Â Â Â Â <------->Â Â Â Â Cu(NH₃)₂ +Â Â Â Br-
IÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0.57 0Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0
CÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â -2x +x Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â +x
EÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â (0.57-2x) xÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â x

K = x²/(0.57 - 2x)² = 396.9

x/(0.57 - 2x) =19.9

x = 11.34 - 39.8 x

40.8 x = 11.34

x = 0.277 M

Solubility (in g/L) of CuBr(s) = 0.277 x (143.45 g/mol) = 39.87 g/L

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