Calculate the pH of each of the solutions and the change in pH to 0.01 pH...

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Chemistry

Calculate the pH of each of the solutions and the change in pHto 0.01 pH units caused by adding 10.0 mL of 2.05-M HCl to 570. mLof each of the following solutions.
a) waterÂ Â
before mixing = 7
After mixing = 1.45
b) 0.135 MC₂H₃O₂^1-
^{Before mixing = 8.95}
^{After mixing = ?}
c) 0.135 M HC₂H₃O₂
_{Before mixing = ?}
_{After mixing = ?}
d) a buffer solution that is 0.135 M in eachC₂H₃O₂^1- andHC₂H₃O₂
_{Before mixing = ?}
_{After mixing = ?}
I've tried this so many times and I don't understand it. Isthere a formula or a set of formulas for this ?? Can someone pleasejust spell it out for me step by step and why. Please and thankyou!

Answer & Explanation Solved by verified expert

3.8 Ratings (729 Votes)

a water Before mixing pH 700 After mixing H is provided by HCl H 10205580 0035 Hence pH logH 145 pH change 7145 555 b 0135 M C2H3O21 Before mixing C2H3O21 H2O CH3COOH OH Kb CH3COOH OH C2H3O21 CH3COOH OHH C2H3O21H KwKa Notice here CH3COOH and OH are generated in pairs hence CH3COOH OH and Kb KwKa CH3COOH OH C2H3O21 OH2C OH CKwKa H KwOH KwKaC logH See Answer

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