Calculate the pH of a 25 mg/L solution of hydrofluroic acid. HF = H+ + F-...
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Calculate the pH of a 25 mg/L solution of hydrofluroic acid.
HF = H+ + F- Ka=10^-3.2
Calculate the pH of a 25 mg/L solution of hydrofluroic acid.
HF = H+ + F- Ka=10^-3.2
Answer & Explanation Solved by verified expert
25 mg / L = 25 x 10^-3 g / L
molarity = 25 x 10^-3 / 20 mol / L
              = 0.00125 M
HF <------------------> H+ + F-
0.00125Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0Â Â Â Â Â Â Â Â Â 0Â Â -------------> initial
-x                               +x         +x ------------> change
0.00125-x                  x          x -------------> equilibrium
Ka = [H+][F-]/[HF]
10^-32 = x^2 / 0.00125 - x
x^2 + 6.31 x 10^-4 x - 7.89 x 10^-7 = 0
x = 6.27 x 10^-4
x = [H+] = 6.27 x 10^-4 M
pH = -log
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