Calculate the pH of a 0.89 M methylamine solution.

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Chemistry

Calculate the pH of a 0.89 M methylamine solution.

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4.5 Ratings (694 Votes)

CH3NH2 + H2O <----------------------> CH3NH3+Â Â + OH-

0.89Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0 ------------------> initial

0.89-xÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â xÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â x ---------------> equilibrium

Kb = [CH3NH3+][OH-]/[CH3NH2]

Kb = x^2 / 0.89-x

4.2 x 10^-4 =x^2 / 0.89-x

x^ + 4.2 x 10^-4Â Â x - 3.738 x 10^-4 = 0

x = 0.019

x = [OH-] = 0.019 M

pOH = -log [OH-] = -log (0.019) = 1.72

pH + pOH = 14

pH = 12.28

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Calculate the pH of a 0.89 M methylamine solution.

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Chemistry

Calculate the pH of a 0.89 M methylamine solution.

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