Calculate the PH after the addition of 0.00, 5.00, 15.00, 25.00, 40.00, 45.00,49.00, 50.00, 51.00, 55.00...

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Chemistry

Calculate the PH after the addition of 0.00, 5.00, 15.00, 25.00,40.00, 45.00,49.00, 50.00, 51.00, 55.00 and 60mL of 0.100M HCl inthe tirtration of 50.00mL of 0.100M weak Monoprotic base B. Kb of Bis 9.52 *10^-7

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3.9 Ratings (411 Votes)

a No acid added B H2O BH OH let x amount has hydrolyzed Kb 952 x 107 x201 x OH 308 x 104 M pOH logOH 351 pH 14 pOH 1049 b after 5 ml of 01 M HCl moles of base molarity x volume 01 x 005 5 x 103 mols moles of acid added 01 x 0005 5 x 104 mols So 5 x 104 mols of acid is neutralized by 5 x 104 mols of base remaining base 5 x 103 5 x 104 45 x 103 mols molarity of salt 5 x 1040005 005 91 x 103 M molarity of base 45 x 1030005 005 0082 M Using HendersenHasselbalck equation pH pKa logbaseacid Ka KwKb 1 x 1014952 x 107 105 x 108 pKa logKa 798 pH 798 log008291 x 103 893 c after 15 ml of 01 M HCl moles of base molarity x volume 01 x 005 5 x See Answer

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