Calculate the ph after mixing 100 ml of .075 M ammonium chloride with 76 ml of...

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Chemistry

Calculate the ph after mixing 100 ml of .075 M ammonium chloridewith 76 ml of .1 M LiOH

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4.3 Ratings (686 Votes)

NH4Cl millimoles = 100 x 0.075 = 7.5

LiOH millimoles = 76 x 0.1 = 7.6

NH4Cl + LiOH ----------------------------> NH4OH + LiCl

7.5Â Â Â Â Â Â Â Â Â Â 7.6Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0 ----------------> initial

0Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0.1Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 7.5Â Â Â Â Â Â Â Â Â Â Â Â 7.5

LiOH is strong base . so pH decided by LiOH

LiOH concentration = millimoles / total volume

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 0.1 / 100+ 76

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 5.68 x 10^-4 M

pOH = -log [OH-] = -log (5.68 x 10^-4) = 3.25

pH +pOH =14

pH = 10.75

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