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Calculate the percent ionization in a 0.1M solution of hydrofluoric acid (Ka=3.53*10^-4)

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Chemistry

Calculate the percent ionization in a 0.1M solution ofhydrofluoric acid (Ka=3.53*10^-4)

Answer & Explanation Solved by verified expert
3.6 Ratings (297 Votes)

HF <------->   H+ +  F-

Initial            0.1                     0         0

Change         - x                     +x       +x

Equilibrium (0.1-x)                  x         x

Ka = 3.53 * 10-4 = x. x / (0.1-x)

x = 0.005767

Percent ionization = ( Ionized concentration / unionizedconcentration ) * 100

                           = ( 0.005767 / 0.1) * 100

                           =5.767 %
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