CALCULATE THE NUMBER OF FRENKEL DEFECTS PRESENT IN A CRYSTAL OF AgCl at 300 K, GIVEN...

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CALCULATE THE NUMBER OF FRENKEL DEFECTS PRESENT IN ACRYSTAL OF AgCl at 300 K, GIVEN THAT THE MATERIAL HAS A CUBE UNITCELL OF EDGE 0.555 nm THAT CONTAINS 4 A g ATOMS. ASSUME THAT THEINTERSTITIAL ATOMS OCCUMY ANY OF 8 TETRAHEDRAL SITES IN THE UNITCELL. Hf = 2.69 x 10^-19 L

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4.3 Ratings (527 Votes)

number of Frankel defects = (square root of ( N * Ni)) * e^(-dH/2RT)

N = number of atoms present in unit cell

Ni = number of interstial positions

dH = enthalpy of formation for frankel defect

R = gas constant

T = absolute temperature

Number of Frankel defects = (square root of ( N * Ni)) * e^(-dH/2RT)

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = (square root of (4 * 8)) * e^((2.69*10^-19)/(2*8.314*300))

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 1

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