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Calculate the molarity (M) of 150.6 g of H2SO4 in 1.290 L of solution.

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Chemistry

Calculate the molarity (M) of 150.6 g of H2SO4 in 1.290 L ofsolution.

Answer & Explanation Solved by verified expert
4.0 Ratings (573 Votes)

Mass of H2SO4 = 150.6 g

Volume of solution = 1.290 L

Moarity(M) =    moles of solute/liters of solution

Moles of solute(H2SO4) = mass of solute/molar mass of solute

                                            = 150.6 g/98.079 g/mol

                                            = 1.535 mol

So ,

Molarity (M) = 1.535 mol/1.290 L

                        = 1.18 M
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