Calculation
To prepare 2 M of 25 ml NH4Cl solution
mass of NH4Cl required = molarity x molar mass c volume (L)
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= 2 M x 53.5 g/mol x 0.025 L
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= 2.675 g
To prepare 2 M of 25 ml CaCl2 solution
mass of CaCl required = molarity x molar mass c volume (L)
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= 2 M x 110.98 g/mol x 0.025 L
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          =
5.049 g