Initially I- will only come from KI
KI ----> K+ + I-
3.0 mL of 0.20 M KI
Nmber of moles of I- = M*V
                                           Â
= 0.2 M * 3 mL
                                           Â
= 0.6 mmol
Total volume of solution = 3 mL + 5 mL + 5 mL + 6 mL + 1
mL = 20 mL
concentration of I- = number of moles of I- / volume of
solution
                                     Â
= 0.6 mmol/ 20 mL
                                     Â
= 0.03 M
Answer: 0.03 M
