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Calculate the grams of K2CO3 required to prepare 510.0 mL of a 0.777 g/L K+ solution....

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Chemistry

Calculate the grams of K2CO3 required toprepare 510.0 mL of a 0.777 g/L K+ solution. [Answer in4 SF].

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3.9 Ratings (699 Votes)

0.777 g/L K+ solution means 0.777g of K+ present in 1L of solution

                                    1L of solution contains 0.777g of K+

   1000ml of solution contains 0.777g of K+

510ml of solution contains = 0.777*510/1000   =0.39627 g of K+

                                  2*39g of K+ obtain from 138g of k2CO3

                                0.39627G OF k+ obtain from= 138*0.39627/2*39   = 0.701g of K2CO3
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