Calculate the concentration of free mercury (II) ion, [Hg2+], in an aqueous solution that is initially...
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Calculate the concentration of free mercury (II) ion,[Hg2+], in an aqueous solution that is initially 0.16 MHg(NO3)2 and 3.2 M NaCl given that theKf of HgCl42- is1.7*1016.
The answer is 2.2*10-19 M, how?
Calculate the concentration of free mercury (II) ion,[Hg2+], in an aqueous solution that is initially 0.16 MHg(NO3)2 and 3.2 M NaCl given that theKf of HgCl42- is1.7*1016.
The answer is 2.2*10-19 M, how?
Answer & Explanation Solved by verified expert
The equation for the complexation reaction is
       Hg+2              + 4 Cl-        -------> [HgCl4]-2
     0.16M                 3.2M                      0      initial concentrations
  0.16-x                  3.2-4x                      x      after reaction
Thus Kf = x/
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