As in the given problem
Zn(s)+Sn2+ ------------->
Zn2+(aq)+Sn(s)
Zinc oxidized and tin
reduces
Zinc will act as an anode and tin as a cathode
Than standard reduction potential of the cell = Eo
cathode- Eo Anode
                                                                               Â
   = -0.14 – (-0.76) (from electrochemical
series)
                                                                                  Â
= 0.62 volts
E cell = Eocell – RT/nF log
[con of oxidized form] /[con of reduced form]
        = 0.62 –
0.0591/2 log (0.763/ 0.0140)
        = 0.62 –
0.0591/2 log 54.4
        = 0.62 -
0.02955 X 1.73
        = 0.62 -
0.0512
    = 0.5688 volts
