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Calculate ΔG° for the following reaction as written Ni2+ (aq) + Sn (s) → Ni (s)...

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Chemistry

Calculate ΔG° for the following reaction as written

Ni2+ (aq) + Sn (s) → Ni (s) + Sn2+(aq)

given the following reduction half-reactions and standardreduction potentials.

Sn2+ (aq) + 2 e- → Sn (s)     E° = -0.15V

Ni2+ (aq) + 2 e- → Ni (s)     E° = -0.25V

Answer & Explanation Solved by verified expert
3.9 Ratings (517 Votes)

anode reaction: oxidation takes place

Sn(s) -------------------------> Sn+2 (aq) + 2e-   ,   E0Sn+2/Sn = - 0.15 V

cathode reaction : reduction takes palce

Ni+2(aq) + 2e- -----------------------------> Ni(s) , E0Ni+2/Ni = -0.25V

--------------------------------------------------------------------------------

net reaction: Ni2+ (aq) + Sn (s) → Ni (s) + Sn2+ (aq)

E0cell= E0cathode- E0anode

E0cell= E0Ni+2/Ni - E0Sn+2/Sn

          = -0.25 - (-0.15)

          = -0.10 V

detla G0 = -nF Ecell0

              = - 2x 96, 485 x (-0.10)

              = 19297 J

               = 19.3 kJ

ΔG° = 19.3 kJ
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