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Calculus

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c1 e 1 16 c2 e 4 t 3 c1 e 1 12 c2 e 4 t 4 c1 e 1 c2 e 4 t 2 5 3 e 1 7 e 4 t 3c1e 1 12c2e 4t b Find x 1 if x 0 4 and x 0 2 x t 2 5 3e t 7e 4t c e 16c e4 3c e 12c e4 help formulas 4 c e c e 4 c1e t c2e 4t 7e4 correct least one of the answers above is NOT correct point Suppose x c e c e t a Verify that x c e c e is a solution to x 3x 4x 0 by substituting it into the differential equation Enter the terms in the orde given Enter c as c1 and c as c2 c1e t 16c2e 4t 0 help formulas correct correct incorrect

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