Billiard ball A of mass mA = 0.122 kg moving with speed vA = 2.80 m/s...

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Physics

Billiard ball A of mass mA = 0.122 kg moving with speed vA =2.80 m/s strikes ball B, initially at rest, of mass mB = 0.145 kg .As a result of the collision, ball A is deflected off at an angleof θ′A = 30.0∘ with a speed v′A = 2.10 m/s, and ball B moves with aspeed v′B at an angle of θ′B to original direction of motion ofball A.

1) Solve these equations for the angle, θ′B,of ball B after the collision. Do not assume the collisionis elastic.

2)Solve these equations for the speed, v′B, ofball B after the collision. Do not assume the collision iselastic.

Answer & Explanation Solved by verified expert
3.7 Ratings (664 Votes)
use the law of conservation of momentum as mA vA mA vA mB vB 0 0122 28 10 0122    See Answer
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