Be sure to answer all parts. The equilibrium constant Kc for the Reaction: H2(g) + CO2(g) <-->...

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Chemistry

Be sure to answer all parts.
The equilibrium constant Kc for the Reaction:
H2(g) + CO2(g) <--> H2O(g) + CO(g) is 4.2 at 1650 C.Initially 0.87 mol H2 and 0.87 mol CO2 are injected into a 4.9 Lflask. Calculate the concentraion of each species atequilibrium
Equilibrium concentration of H2: __ M
Equilibrium concentraion of CO2: _ M
Equilibrium concentraion of H2O: _M
Equilibrium concentration of CO: __M

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4.5 Ratings (901 Votes)

The equilibrium constant Kc for the Reaction:

H2(g) + CO2(g) <--> H2O(g) + CO(g) is 4.2 at 1650 C. Initially 0.87 mol H2 and 0.87 mol CO2 are injected into a 4.9 L flask. Calculate the concentraion of each species at equilibrium

Solution :

Lets find out concentration of each species.

[H2]= 0.87 mol /4.9 L =0.178 M

[CO2]= 0.87 mol / 4.9 L = 0.178 M

Now we write the reaction and set up the ICE chart

Â Â Â Â Â Â Â Â Â H2(g) + CO2(g) <--> H2O(g) + CO(g)

IÂ Â Â Â Â Â 0.178Â Â Â Â Â Â 0.178 Â Â Â Â Â Â Â Â Â Â Â Â Â 0Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0

CÂ Â -xÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â -xÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â +xÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â +x

E (0.178

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