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Be sure to answer all parts. If 2.00 mL of 0.100 M NaOH are added to 1.000...

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Chemistry

Be sure to answer all parts.

If 2.00 mL of 0.100 M NaOH are added to

1.000 L

of

0.800 M CaCl2,

what is the value of the reaction quotient and will precipitationoccur?

Q =  

×

10 (Enter your answer in scientific notation.)
  

Precipitation will occur.

  

Precipitation will not occur.

Answer & Explanation Solved by verified expert
3.6 Ratings (582 Votes)

no of moles of NaOH = molarity * volume in L

                                   = 0.1*0.002   = 0.0002 moles

   NaOH ----------> Na+ + OH-

                                        0.0002 moles

      [OH-]   = no of moles/volume in L

                 = 0.0002/1.002   = 0.0002M

no of moles of CaCl2 = molarity * volume in L

                                     = 0.8*1 = 0.8moles

CaCl2 -------------> Ca+2 + 2Cl-

0.8 moles                0.8 moles

[Ca+2]   = no of moles/volume in L

             = 0.8/1.002   = 0.798 M

Qsp = [Ca+2][OH-]2

          = 0.798*(0.0002)2 = 3.2*10-8

ksp of Ca(OH)2 = 5.02*10-8

Ksp>Qsp will not form precipitate

Precipitation will not occur.
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