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Background: A 102.4 mL sample of 0.110 M methylamine (CH3NH2, Kb=3.7×10−4) is titrated with 0.230 M...

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Chemistry

Background: A 102.4 mL sample of 0.110 M methylamine (CH3NH2,Kb=3.7×10−4) is titrated with 0.230 M HNO3. Calculate the pH afterthe addition of each of the following volumes of acid.

A.) 0.0 mL

B.) 24.5 mL

C.) 49.0 mL

D.) 73.5 mL

Answer & Explanation Solved by verified expert
3.6 Ratings (655 Votes)
HNO3 CH3NH2 CH3NH3 NO3 CH3NH2 accepts a H forming its conj acid A Kb x20105 37104 x20105 x2 3885 x 105 x OH 000623 M logOH pOH 22055 pH 14 pOH pH 14 22055 1179 B Moles HNO3 00223 L x 0270 molL 0006021 mol Moles initial CH3NH2 01148 L x 0105 M 0012054 mol    See Answer
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