Azulene is a beautiful blue hydrocarbon consisting of only C and H atoms. If 0.106 g...

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Azulene is a beautiful blue hydrocarbon consisting of only C andH atoms. If 0.106 g of the compound is burned in oxygen, 0.364 g ofCO₂ and 0.0596 g of H₂O are made. Determinethe empirical formula of azulene from this data. [ Hint: Firstconvert the masses of CO₂ and H₂O to moles,then convert the moles found to moles of C to H. ]

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4.4 Ratings (669 Votes)

C%Â Â = 12*wt of CO2*100/44*wt of compound

Â Â Â Â Â Â Â Â Â Â Â = 12*0.364*100/44*0.106Â Â = 93.65%

H%Â Â Â Â = 2*wt of H2O *100/18*wt of compound

Â Â Â Â Â Â Â Â Â Â Â Â = 2*0.0596*100/18*0.106Â Â Â = 6.25%

ElementÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â %Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â A.wtÂ Â Â Â Â Â Â Â Â Â Â no of molesÂ Â Â Â Â Â Â Â Â Â Â Â Â Â simple ratioÂ Â Â Â Â Â Â Â Â Â Â Â simplest ratio

CÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 93.65Â Â Â Â Â Â Â Â Â Â Â Â Â 12Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 93.65/12Â Â = 7.8Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 7.8/6.25Â Â = 1.248Â Â Â Â Â Â Â 1.248*4 = 5

HÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 6.25Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 1Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 6.25/1Â Â Â Â Â Â = 6.25Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 6.25/6.25 = 1Â Â Â Â Â Â Â Â Â Â Â Â Â Â 1*4Â Â Â Â Â Â = 4

The empirical formula of Azulene = C5H4

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