At the AQWA facility in Hillarys, patrons view the marine life while walking through a tunnel...

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At the AQWA facility in Hillarys, patrons view the marine lifewhile walking through a tunnel formed by a semi-cylinder glasswall. The aquarium contains sea water (Specific Gravity 1.025), andthe highest point of the glass wall lies 8 metres below the watersurface. If a section of the glass wall is 2.5 metres in radius and10 metres long, determine the magnitude and direction of the forceexerted on the section.
ï¼ˆThis is Chemical Engineering question (about Hydrostatics/ShellMomentum Balances), please help me to solve it, thanks)

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3.8 Ratings (484 Votes)

vol of water above glass wall = cross-section of wall * height of water on class wall

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = Pie * r^2 * h

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â =ss/7 * (2.5)^2 * 8 = 157.142

Weight of water above glass wallÂ Â =Â Â vol * specific gravity * g

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â =Â Â 157.142 * 1.025 *9.8Â Â =Â Â 161.07 * 9.8Â Â =Â Â 1578.486 N

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = magnitude of force ofwater above glass wall on glass wall

Â Â Â Â Force will act in downward direction on glass wall .

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