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Assuming that you start with 2.00 g of sodium benzoate and 5 mL of 3 M...

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Chemistry

Assuming that you start with 2.00 g of sodium benzoate and 5 mLof 3 M HCl, how many molar equivalents of HCl are you using? Usetwo decimal places.

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4.0 Ratings (586 Votes)

mass of sodium benzoate = 2.00 g

molar mass of sodium benzoate= 144.11 g/mol

moles = mass / molar mass

moles of sodium benzoate (C6H5COONa) = 2 / 144.11

                                                                    = 0.0139

moles of HCl = molarity x volume / 1000

                      = 3 x 5 / 1000

                      = 0.015

C6H5COONa +    HCl    ---------------------->   C6H5COOH + NaCl

    1 mol                 1 mol

0.0139 mol        0.015 mol

here limiting reagent is C6H5COONa

so 0.0139 mol of HCl is used.

molar equivalents of HCl = 0.01               (two decimal places)

                       
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