Assume that the firework has a mass of m_0 =0.30~\text{kg}m​0​​=0.30 kg and is launched from a cannonat an angle of \theta_0 = 41.8^\circθ​0​​=41.8​∘​​ with aninitial velocity of | v_0 | = 20~\text{m/s}∣v​0​​∣=20 m/s.Just as the firework reaches its hight point in its trajectory, itexplodes into two pieces. Immediately after the explosion, thefirst piece, with a mass of m_1 = 0.2~\text{kg}m​1​​=0.2kg flies off at an angle \theta_1 = 150^\circθ​1​​=150​∘​​relative to the positive (forward) horizontal axis at a velocity of| v_1 | = 5~\text{m/s}∣v​1​​∣=5 m/s relative to theground. Calculate the trajectory angle, \theta_2θ​2​​ ofthe second piece immediately after the explosion. Assume the secondpiece has a mass of m_2 = 0.1~\text{kg}m​2​​=0.1 kg,neglect the effect of air resistance, and report your result as anangle relative to the positive (forward) horizontal axis.
