Assume that the differences are normally distributed. Complete parts ?(a) through ?(d) below. Observation 1 2 3 4 5 6 7 8 Open in StatCrunch + Copy to...

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Assume that the differences are normally distributed. Completeparts ?(a) through ?(d) below.

Observation

1

2

3

4

5

6

7

8

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Upper X Subscript iXi

46.746.7

47.747.7

45.645.6

50.250.2

48.448.4

50.850.8

47.847.8

48.648.6

Upper Y Subscript iYi

50.150.1

48.448.4

47.347.3

54.554.5

47.947.9

50.950.9

49.649.6

50.350.3

?(a) Determine

d Subscript i Baseline equals Upper X Subscript i Baseline minusUpper Y Subscript idi=Xi?Yi

for each pair of data.

Observation

1

2

3

4

5

6

7

8

di

negative 3.4 ?3.4

negative 0.7 ?0.7

negative 1.7 ?1.7

negative 4.3 ?4.3

0.5 0.5

negative 0.1 ?0.1

negative 1.8 ?1.8

negative 1.7 ?1.7

?(Type integers or? decimals.)

?(b) Compute

d overbard

and

s Subscript dsd.

d overbardequals=negative 1.650 ?1.650

?(Round to three decimal places as? needed.)

s Subscript dsdequals=1.605 1.605

?(Round to three decimal places as? needed.)?(c) Test if

mu Subscript d?dless than<0

at the

alpha?equals=0.05

level of significance.

What are the correct null and alternative? hypotheses?

A.

Upper H 0H0?:

mu Subscript d?dless than<0

Upper H 1H1?:

mu Subscript d?dequals=0

B.

Upper H 0H0?:

mu Subscript d?dgreater than>0

Upper H 1H1?:

mu Subscript d?dless than<0

C.

Upper H 0H0?:

mu Subscript d?dless than<0

Upper H 1H1?:

mu Subscript d?dgreater than>0

D.

Upper H 0H0?:

mu Subscript d?dequals=0

Upper H 1H1?:

mu Subscript d?dless than<0

Answer & Explanation Solved by verified expert
4.3 Ratings (782 Votes)
SolutionState the hypotheses The first step is tostate the null hypothesis and an alternative hypothesisNull hypothesis ud 0Alternative hypothesis ud 0Note that these hypotheses constitute a onetailed    See Answer
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