Hydrolysis of methylsalicylate with NaOH
moles of methylsalicylate = 4.0 ml x 1.18 g/ml/152.15 g/mol =
0.031 mols
1 mole of methylsalicylate would give 1 mole of salicylic acid
upon reaction
Theoretical yield of salicylic acid = 0.031 mols
                                                   Â
= 0.031 mol x 138.121 g/mol
                                                   Â
= 4.28 g
