Assignment ID is p1

NOTE: Algebraic expressions follow FORTRAN conventions.
Use full calculator precision for intermediate values.


Use the bisection method with the function defined by:

A=(X + 1.62) / 5.39
B=(X - 3.77) / 5.39
P1=((A-1)**2)*(1+2*A)
P2=((B+1)**2)*(1-2*B)
F(X) = (P1 * (-1.24) ) + (P2 * 4.13)

Start with interval (Xleft,Xright) = (-1.62, 3.77)
The function values at these end points are
F(Xleft) = -1.24
F(Xright) = 4.13

The new approximation interval bracketing the root
after ONE bisection is (______1______,______2______).
Function values at these end points are: ______3______, and1.445

The new approximation interval bracketing the root
after ONE MORE bisection is (______4______,______5______).
Function values at these end points are: -0.400937 and______6______.

The new approximation interval bracketing the root
after ONE MORE bisection is (______7______,______8______).

If Xmid satisfies the convergence criterior|f(Xmid)|<=0.00001,
then the root Xmid is ______9______.

ANSWER SECTION:
SELECTIONS FOR BLANK NUMBER 1
(a) 0.73
(b) 1.075
(c) -1.62
(d) -0.21
(e) -0.68
SELECTIONS FOR BLANK NUMBER 2
(a) 1.075
(b) 3.77
(c) -0.235
(d) -0.895
(e) -1.62
SELECTIONS FOR BLANK NUMBER 3
(a) 1.445
(b) -3.23
(c) -1.24
(d) -3.89
(e) 2.07
SELECTIONS FOR BLANK NUMBER 4
(a) 1.075
(b) -0.2725
(c) -2.3525
(d) 1.3875
(e) -1.1025
SELECTIONS FOR BLANK NUMBER 5
(a) 3.525
(b) 2.4225
(c) -0.2725
(d) -0.145
(e) 1.075
SELECTIONS FOR BLANK NUMBER 6
(a) 1.445
(b) 3.29094
(c) 0.575
(d) -0.745
(e) -0.400937
SELECTIONS FOR BLANK NUMBER 7
(a) 1.075
(b) 0.40125
(c) 1.2775
(d) 0.6575
(e) -0.2725
SELECTIONS FOR BLANK NUMBER 8
(a) -1.41875
(b) 1.74875
(c) 0.40125
(d) 2.68125
(e) -0.2725
SELECTIONS FOR BLANK NUMBER 9
(a) 1.8501
(b) 1.4001
(c) 1.74875
(d) -0.829902
(e) 0.0600983