HBr (aq) + NaOHÂ Â -----------------> NaBr (aq) +
H2O (l)
  80.9
g         40
g                            Â
102.9 g       18 g
60.0 g        Â
48.8
g                            Â
here HBr is the limiting reagent.
80.9 g HBr ----------------> 40 g NaOH
     Â
??        Â
-----------------> 48.8 g NaOH
mass of HBr = 48.8 x 80.9 / 40 = 98.7 g
we need 98.8 g HBr. but here we have only 60.0 g HBr. so
this is limiting reagent.
no HBr will left over. all consumed
