apply statistical methods and analysis. Unless otherwisestated, use 5% (.05) as your alpha level (cutoff for statisticalsignificance).
Ice Cream Flavor Preference by Gender
|
| Men | Women | Marginal Row Totals |
Vanilla | 15 | 10 | 25 |
Chocolate | 30 | 5 | 35 |
Marginal Column Totals | 45 | 15 | 60 (Grand Total) |
The chi-square statistic is 5.143. The p-value is .0233.This result is significant at p < .05.
#1. The chart above shows male and femalepreferences for vanilla vs. chocolate ice cream among men andwomen.
- What percent of men prefer chocolate over vanilla?________
- What percent of women prefer chocolate over vanilla?________
- Report the results of the statistical test in plainlanguage:
#2. The calculator at this link will allow youto perform a one-way chi-square or “goodness of fit test”:
http://vassarstats.net/csfit.html
Fifty students can choose between four different professors to takeIntroductory Statistics. The number choosing each professor isshown below. Use the calculator above to test the null hypothesisthat there is no preference for professors -- that there is anequal chance of choosing each of them. Report your resultsincluding chi-square, degrees of freedom, p-value and yourinterpretation. Use an alpha level of .05. Be careful not to overinterpret – state only what the test result tells you.
Professor | N |
Dr. Able | 20 |
Dr. Baker | 8 |
Dr. Chavez | 14 |
Dr. Davis | 8 |
#3. Match these non-parametric statistical testswith their parametric counterpart by putting the correspondingletter on the line.
_____ Friedman test
_____ Kruskal-Wallis H test
_____ Mann-Whitney U test
_____ Wilcoxon Signed-Ranks T test
A: Paired-sample t-test
B: Independent-sample t-test
C: One-way ANOVA, independent samples
D: One-way ANOVA, repeated measures
