An oil drop of mass 50 mg and of charge 5 C is just balanced...

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An oil drop of mass 50 mg and of charge 5 C is just balanced in air against the force of gravity Calculate the strength of the electric field required to balance it g 9 8 ms 2 a 98 NC upwards b 98 NC downwards c 9 8 NC towards north d 9 8 NC towards south

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To find the strength of the electric field required to balance the oil drop against gravity we can use the following steps Given Data Mass of the oil drop m 50 mg 50 times 103 g 50 times 106 kg 5 times 105 kg Charge of the oil drop q 5 C 5 times 106 C Acceleration due to    See Answer
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