An object of mass 0.50 kg is released from the top of a building of height...

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An object of mass 0.50 kg is released from the top of a buildingof height 2 m. The object experiences a horizontal constant forceof 1.1 N due to a wind blowing parallel to the face of thebuilding.
(a) Find the time it takes for the object to strike the ground._s
(b) What is the magnitude of the acceleration of the object?m/s2
(c) Through what horizontal distance does the object move beforeit hits the ground? ___m

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3.8 Ratings (633 Votes)

Â Â Â Given Data

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â m =0.5 kg

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â h=2m

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â F=1.1N

(a)Formula = root(2y/g)Â Â where y=2m

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = root(4/9.81)

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = root(0.4077)

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â =0.6385 sec

(b) Formula A=root(Ax^2+Ay^2)

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Ax=1.1/0.50

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â =2.2 m/s^2

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Ay=9.8 m/s^2

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â A=root(Ax^2+Ay^2)

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = root(4.84+96.23)

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â =root(102.07)

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â =10.53 m/s^2

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â =0.5*2.2*0.47039

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â =0.4484 meters

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An object of mass 0.50 kg is released from the top of a building of height...

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Physics

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