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An experimental protocol calls for 25.4 mL of a solution in which the potassium ion concentration...

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Chemistry

An experimental protocol calls for 25.4 mL of a solution inwhich the potassium ion concentration is 0.0872 M. How would you preparethis solution from pure solid potassium phosphate? (The solvent iswater.)

(Please don’t forget to state how you would prepare the solution; don’t simplycalculate the grams of potassium phosphate required.)

Answer & Explanation Solved by verified expert
4.2 Ratings (735 Votes)
According to solution then M molV mol M x V 00872 molL x 00254 L 22149x103 moles Molar Mass 3x39 31 4x16 212 gmol m mol x MM 22149x103 mol x 212 gmol 04696 g of K3PO4 Now fif K3PO4 is 100 pure you can    See Answer
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